1.if the probabilities are 0.87,0.36 and 0.29 that a family,randomly chosen as part of a sample survey in Adentan,owns a color television set,a video cassette recorder or both,what is the probability that a family in this area will own one,or the other or or both kinds of sets?
2.The probability that a woman trying on a dress ask to have it altered is 0.65,the probability that she will ask to have it delivered to her home is 0.32 and the probability that she will ask to have both done is 0.21.what is the probability that a woman shopping in this store will ask :
I.either to have the dress altered or to have it delivered to her home.
II.neither to have it altered nor to have it delivered to her home.
it's good and very applicable.
To find the probability that a family in Adentan owns either a color television set, a video cassette recorder, or both, you need to use the concept of probabilities union.
1. Given that the probability of owning a color television set is 0.87, the probability of owning a video cassette recorder is 0.36, and the probability of owning both is 0.29, you can calculate the probability of owning either one or the other or both.
To calculate the probability of owning one or the other, you can add the probabilities of owning a color television set and owning a video cassette recorder and subtract the probability of owning both. Mathematically, it can be represented as:
P(owning one or the other) = P(owning a color television set) + P(owning a video cassette recorder) - P(owning both)
= 0.87 + 0.36 - 0.29
= 0.94
Therefore, the probability that a randomly chosen family in Adentan owns either a color television set, a video cassette recorder, or both is 0.94.
2. To find the probability that a woman shopping in the store will ask to have the dress altered or have it delivered to her home:
I. To have the dress altered or delivered, you need to calculate the probability of either event occurring. Therefore, you can add the probabilities of asking for alterations and asking for delivery and subtract the probability of asking for both. Mathematically, it can be represented as:
P(alterations or delivery) = P(ask for alterations) + P(ask for delivery) - P(ask for both)
= 0.65 + 0.32 - 0.21
= 0.76
Therefore, the probability that a woman shopping in the store will ask to have the dress altered or have it delivered is 0.76.
II. To find the probability of neither asking for alterations nor delivery, you need to find the complement of the probability of asking for either alterations or delivery. In other words:
P(neither alterations nor delivery) = 1 - P(alterations or delivery)
= 1 - 0.76
= 0.24
Therefore, the probability that a woman shopping in the store will neither ask for alterations nor delivery is 0.24.