A transformer with 1890 turns in its primary coil has to decrease the voltage from 4620 V to 220 V for home use. How many turns should there be on the secondary coil?
To determine the number of turns on the secondary coil, we can use the formula for transformer voltage ratio:
(Vp / Vs) = (Np / Ns)
Where:
- Vp is the voltage in the primary coil (4620 V in this case)
- Vs is the voltage in the secondary coil (220 V in this case)
- Np is the number of turns in the primary coil (1890 turns in this case)
- Ns is the number of turns in the secondary coil (unknown, what we need to find)
First, let's rearrange the formula to solve for Ns:
Ns = (Np * Vs) / Vp
Now we can substitute the known values into the formula:
Ns = (1890 * 220) / 4620
Simplifying the equation:
Ns = 0.09090504 * 1890
Finally, we calculate the value of Ns:
Ns ≈ 171.98
Therefore, the number of turns on the secondary coil should be approximately 172.
N=secondaryvoltage/primaryvolts
N=4620/220=41
secondaryturns=N*primaryturns
= 41*1890