What is the pH of a solution made by mixing 1.40 mL of 0.0043 molar Sr(OH)2 with 8.90 mL of 0.0029 molar Sr(OH)2 solution?

moles of OH:

.0014*.0043+.0089*.0029=3.18E-5 moles

M=3.18E-5/(.0014+.0089)=.00309

p(OH)=-log .00309 =2.51
pH=14-pOH=....