. Okay 2HgO turns into 2hg + O2.

What mass of Co2 can be produced from 25.0g of Fe3O4 ?

To find the mass of CO2 produced from 25.0g of Fe3O4, we need to use the balanced chemical equation and the concept of stoichiometry.

First, let's write the balanced chemical equation for the reaction:
Fe3O4 + CO -> Fe + CO2

From the equation, we can see that 1 mole of Fe3O4 reacts with 1 mole of CO, producing 1 mole of Fe and 1 mole of CO2.

Next, we need to calculate the moles of Fe3O4 using its molar mass. The molar mass of Fe3O4 can be calculated as follows:
Molar mass of Fe3O4 = (molar mass of Fe x 3) + (molar mass of O x 4)

Molar mass of Fe = 55.85 g/mol (atomic mass of Fe)
Molar mass of O = 16.00 g/mol (atomic mass of O)

Molar mass of Fe3O4 = (55.85 g/mol x 3) + (16.00 g/mol x 4)
Molar mass of Fe3O4 = 159.70 g/mol + 64.00 g/mol
Molar mass of Fe3O4 = 223.70 g/mol

Now, we can calculate the moles of Fe3O4 by using the given mass and molar mass:
Moles of Fe3O4 = Mass / Molar mass
Moles of Fe3O4 = 25.0 g / 223.70 g/mol

Next, based on the balanced equation, we know that 1 mole of Fe3O4 produces 1 mole of CO2. Therefore, the number of moles of CO2 produced is equal to the moles of Fe3O4.

Finally, we need to calculate the mass of CO2 produced:
Mass of CO2 = Moles of CO2 x Molar mass
Mass of CO2 = Moles of Fe3O4 x Molar mass of CO2

The molar mass of CO2 is calculated as follows:
Molar mass of CO2 = (molar mass of C x 1) + (molar mass of O x 2)

Molar mass of C = 12.01 g/mol (atomic mass of C)
Molar mass of O = 16.00 g/mol (atomic mass of O)

Molar mass of CO2 = (12.01 g/mol x 1) + (16.00 g/mol x 2)
Molar mass of CO2 = 12.01 g/mol + 32.00 g/mol
Molar mass of CO2 = 44.01 g/mol

Now, we can calculate the mass of CO2 produced by substituting the values:
Mass of CO2 = Moles of Fe3O4 x Molar mass of CO2
Mass of CO2 = (25.0 g / 223.70 g/mol) x 44.01 g/mol

Calculate this expression to find the mass of CO2 produced.

I assume you must have some connection to the two equations.