How would you prepare 750 ml of a 10 fold dilution of a 17 M solution of acetic acid?

How would you prepare 200 ml of a 20 fold dilution of a 17 M solution of acetic acid?
please explain and show me the calculations.

To prepare a 10-fold dilution of a 17 M solution of acetic acid, you will need to dilute the initial solution with a solvent, such as water, by a factor of 10.

First, you need to determine the volume of the final solution. In this case, the final volume is given as 750 mL.

Next, you need to calculate the volume of the concentrated solution required to achieve the desired dilution. To do this, you can use the formula:

V1 * C1 = V2 * C2

Where:
V1 = volume of the concentrated solution
C1 = concentration of the concentrated solution
V2 = volume of the final solution
C2 = desired concentration of the final solution

Plugging in the given values:
V1 * 17 M = 750 mL * 10^-1 M

Rearranging the equation to solve for V1:
V1 = (750 mL * 10^-1 M) / 17 M
V1 = 4.41 mL

Therefore, to prepare 750 mL of a 10-fold dilution of a 17 M solution of acetic acid, you will need to mix 4.41 mL of the concentrated acetic acid solution with 745.59 mL of the solvent (water).

Similarly, to prepare a 20-fold dilution of a 17 M solution of acetic acid, you would follow a similar process. Given that the final volume is 200 mL:

V1 * 17 M = 200 mL * 10^-1 M

Rearranging the equation to solve for V1:
V1 = (200 mL * 10^-1 M) / 17 M
V1 = 1.18 mL

To prepare 200 mL of a 20-fold dilution, you would mix 1.18 mL of the concentrated acetic acid solution with 198.82 mL of the solvent.