A 2 kg block of ice is placed in a container at 0 °C. How much energy is required to completely melt the block of ice? (Specific latent heat of fusion for ice = 334 J/g.)

A little confused as to what formula to use for this

334 * 2000 = 668,000 J

To determine the amount of energy required to completely melt the block of ice, you can use the formula:

Q = m * L

where:
Q is the heat energy required (in joules),
m is the mass of the ice block (in kilograms), and
L is the specific latent heat of fusion (in joules per gram).

First, convert the mass of the ice block from grams to kilograms. Since the mass of the ice block is given as 2 kg, there is no need to convert it.

Next, we need to convert the specific latent heat of fusion from joules per gram to joules per kilogram. The given value of specific latent heat of fusion is 334 J/g. To convert it to joules per kilogram, divide it by 1000 to get 0.334 J/g.

Now, you can calculate the heat energy required to completely melt the ice block:

Q = m * L
= 2 kg * 0.334 J/g
= 0.668 J

Therefore, the energy required to completely melt the 2 kg block of ice is 0.668 joules.