i need help finding the slope of the line that passes through each pair of poinst.
1. (1,-3),(4,3)
2.(5,0), (-2,1)
Divide (y2 - y1) by (x2 - x1). For (1), this would be 6/3 = ?
Thank you. The first one came out to 2.
The second one is not working out. I got 4 1/2 and I know that's not correct. I did (-2x2)-(5x1) divide by
(1x2)-(0x1)= -9/2
Don't multiply. (x2-x1) just means taking the second x value and subtracting the first x value from it. So as far as the x values go for the second problem, you'll have (-2 -5). As far as the y's go, you take the second y and subtract the first y. (1-0).
Can you get it from there?
Amy :)
I think I got it.
I redid both.
(1,-3) (4,3); 3-(-3)=6 divided by 4-1=3
(5,0) (-2,1); 1-0=1 and -2-5=-7 so -1/7 is the slope. I hope that's correct?
(1-0)/(-2-5) = -1/7, so that's correct.
YEA!
YEA!
Congratulations! You correctly found the slopes of both lines.
To find the slope of a line passing through two points (x1, y1) and (x2, y2), you can use the formula:
slope = (y2 - y1) / (x2 - x1)
For the first question, you had the points (1, -3) and (4, 3).
Using the formula:
slope = (3 - (-3)) / (4 - 1) = 6 / 3 = 2
So, the slope of the line passing through those points is 2.
For the second question, you had the points (5, 0) and (-2, 1).
Using the formula:
slope = (1 - 0) / (-2 - 5) = 1 / (-7) = -1/7
So, the slope of the line passing through those points is -1/7.
Remember to be careful with signs and make sure to calculate the differences correctly. Keep up the good work!