construct a triangle PQR in which pq=5.5cm angle p=75° and pr=5cm?
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To construct triangle PQR with given information, follow these steps:
1. Start by drawing a line segment PQ of length 5.5 cm.
2. At point P, construct an angle of 75 degrees using a protractor.
3. From point P, measure a line segment PR of length 5 cm in the direction of the angle. Label the endpoint as R.
4. Finally, connect points Q and R with a line segment. Label the point of intersection as Q.
Your triangle PQR is now constructed with PQ = 5.5 cm, angle P = 75 degrees, and PR = 5 cm.
To construct triangle PQR with the given information, follow these steps:
1. Draw a line segment PQ of length 5.5 cm.
2. At point P, construct an angle of 75 degrees using a protractor. This will be angle P.
3. From point P, draw a line segment PR of length 5 cm, making an angle of 75 degrees with PQ. This will be line segment PR.
4. The intersecting point of QR and line segment PR will be point R.
You have now successfully constructed triangle PQR with PQ = 5.5 cm, angle P = 75 degrees, and PR = 5 cm.