physics

four forces act on a hot air ballon
356 N north
129 N west
297 N east
156 N south

a)find the magnitude of the resultant force on the balloon.

i already found this one out.
i got magnitude to be 261.197N

b) find the direction of the resultant force (in relation to the 297 N force, with up being positive)
i cant figure this one out



may someone please help me

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  1. change the S to -N, and the E to -W

    356N-156N + 129W - 297W
    Now get the N, W components..

    200N - 168W. SO it is towards the NE, the angle will be arctan 200/168

    check my math, I did it in my head.

  2. yeah the math is right.
    but i don't get this part:
    ok i know that to solve for angle "a'

    tan(a) = 200/168
    a = arctan(200/168)
    a = arctan(1.19047619)
    a = ?????

    what is arctan?
    is it the same as doing tangent(1.1904)

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    posted by Claudia
  3. arctan is the angle whose tangent is ....
    Some use invtan meaning the same.
    Some write it like this tan^-1 (xxxx)

  4. oh!!! ok thank you
    yeah we use tan^-1
    i was confused on what arctan meant
    but thanks

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    posted by Claudia

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