arithmetic progression

four positive integers form an arithmetic progression . if the product of the first and the last terms is 70 and the second and third terms are 88, find the first term

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  1. a(a+3d) = 70
    (a+d)(a+2d) = 88

    Since 88=8*11, I'd guess that
    T2=8 and T3 = 11

    so, that makes T1=5 and T3=15

    or, you can solve the equations using algebra.

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