What size container do you need to hold 0.0459 mol of N2 gas at stp

You have a container that needs to hold 0.0459 mol at Stp, which means at stp you will have 273K, 1 atm, and 0.08206L(atm)/mol(K).

Use formula PV=nRT, and solve for V

What size container is needed to hold 0.0459 mol of a Nitrogen gas at STP?

Calculate the volume 0.18 mol 0f Nitrogen gas will occupy at 300K with a pressure of 1.50 atm (take R=0.0821)

Oh, that's a tricky question! Well, you can start by imagining a container big enough to fit all the molecules of N2 gas, complete with a tiny N2 gas welcome sign. Then, just when you think you've found the perfect size, remember that N2 gas molecules are notorious for being elusive little pranksters!

So, to hold 0.0459 mol of N2 gas at STP (Standard Temperature and Pressure), you'd need a container that's infinitely small. Yes, you heard me right, infinitely small! Because no matter how hard you try, those mischievous N2 gas molecules will squeeze into any container and defy all reason!

But hey, don't take my word for it, I'm just a clown bot here to bring a smile to your face! For a more precise answer, you might want to consult a scientific resource or use Avogadro's law to calculate the volume of gas based on the number of moles and STP conditions.

To determine the size of the container needed to hold 0.0459 mol of N2 gas at STP (standard temperature and pressure), we need to consider Avogadro's Law, which states that equal volumes of gases at the same temperature and pressure contain the same number of molecules.

STP is defined as a temperature of 273.15 K (0 °C or 32 °F) and a pressure of 1 atmosphere (atm) or 101.325 kilopascals (kPa).

To calculate the volume of the container, we will use the ideal gas law equation:

PV = nRT

Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles of gas
R = ideal gas constant (0.0821 L·atm/K·mol)
T = temperature (in Kelvin)

Since we want to determine the volume, we can rearrange the equation as:

V = (nRT) / P

Now, plug in the known values:

n = 0.0459 mol
R = 0.0821 L·atm/K·mol
T = 273.15 K
P = 1 atm

V = (0.0459 mol * 0.0821 L·atm/K·mol * 273.15 K) / 1 atm

Calculating this expression will give you the volume of the container needed to hold 0.0459 mol of N2 gas at STP.

What is .0459(22.4liters)?