a 12.0 gallon gasoline tank holds 66.0 pounds of gasoline. If this gasoline cost $3.50/gallon, what is the cost of 1 gram of gasoline..
I need help with just the set up part.. I don't know where to start.. help please
you want to find $/g. So, start working with the units:
12.0gal/66lb * 3.50 $/gal * 1lb/454g = $0.0014/g or .14ยข/g
To find the cost of 1 gram of gasoline, we need to set up a proportion using the given information.
First, we need to convert the 12.0 gallons into grams. Since 1 gallon is approximately equal to 3785.41 grams, we can find the total number of grams in the tank:
12.0 gallons * 3785.41 grams/gallon = total grams in the tank
Next, we can set up the proportion to find the cost of 1 gram of gasoline:
66.0 pounds / (total grams in the tank) = $3.50/gallon
Simplifying this equation will give us the cost of 1 gram of gasoline.
To find the cost of 1 gram of gasoline, we need to determine the cost of gasoline per gram.
First, we need to find the total cost of the gasoline in the tank.
To do this, we multiply the number of gallons in the tank by the cost per gallon:
Cost = 12.0 gallons * $3.50/gallon
Next, we need to convert the weight of the gasoline from pounds to grams.
To convert pounds to grams, we use the conversion factor:
1 pound = 453.592 grams
Now, we can calculate the weight of gasoline in grams:
Weight in grams = 66.0 pounds * 453.592 grams/pound
Finally, to find the cost of 1 gram of gasoline, we divide the total cost of gasoline by the weight of gasoline in grams:
Cost per gram = Cost / Weight in grams
By substituting the given values into these equations, you can find the cost of 1 gram of gasoline.