How would you solve this using a chart?
Rodney sold twice as many cars as Greg. In April, Rodney sold 5 fewer cars than he did in March, whereas Greg sold 3 more cars than he did in March. If they sold the same number of cars in April, how many cars did each sell in March?
Greg in march = x
Rod in March = 2x
Rod in April = 2x-5
Greg in April = x + 3
so
2x - 5 = x + 3
x = 8
2x = 16
Thank you!
To solve this problem using a chart, we can create a table to organize the given information and find a solution.
First, let's assign variables to the unknown quantities. Let "R" represent the number of cars Rodney sold in March and "G" represent the number of cars Greg sold in March.
Based on the information given, we can create the following table:
| Rodney | Greg | Total |
---------------------------------------
March | R | G | |
---------------------------------------
April | R-5 | G+3 | |
---------------------------------------
Total | | | |
Next, let's fill in the chart using the information given.
We know that Rodney sold twice as many cars as Greg. Therefore, we can write the equation:
R = 2G
In April, Rodney sold 5 fewer cars than he did in March, so we can write the equation:
R-5 = G
Greg sold 3 more cars than he did in March, so we can write the equation:
G+3 = G
Since they sold the same number of cars in April, we can equate the April columns as follows:
R-5 = G+3
Now, let's solve the equations to find the values for R and G.
First, let's solve the equation R=2G by substituting G=R-5 into it:
R = 2(G)
R = 2(R-5)
R = 2R - 10
-R = -10
R = 10
Now we can substitute R=10 into the equation R-5=G:
10-5 = G
G = 5
Therefore, Rodney sold 10 cars in March and Greg sold 5 cars in March.