Calculate the solubility (in grams per 1.00×10^2 mL of solution) of magnesium hydroxide in pure water.
To calculate the solubility of magnesium hydroxide in water, we need to first understand the concept of solubility and use the given information to find the solubility value.
Solubility refers to the maximum amount of solute that can dissolve in a given amount of solvent at a particular temperature. It is usually expressed in grams of solute per milliliter (mL) of solution.
For magnesium hydroxide, we will assume that it completely dissociates into magnesium ions (Mg2+) and hydroxide ions (OH-) in water, as it is an ionic compound.
The formula for magnesium hydroxide is Mg(OH)2, which indicates that for every one molecule of the compound, we will get one magnesium ion (Mg2+) and two hydroxide ions (OH-).
Now, to find the solubility of magnesium hydroxide, we need to determine the concentration of magnesium hydroxide in the given volume of water (1.00×10^2 mL).
However, we haven't been provided with any specific information regarding the concentration or molarity of the solution. Without this information, it is not possible to calculate the solubility of magnesium hydroxide in pure water.
If we have additional information such as the molar solubility or molarity of the solution, we can use that data to calculate the solubility.
Look up Ksp for Mg(OH)2.
.........Mg(OH)2 --> Mg^2+ + 2OH^-
I........solid.......0........0
C........solid.......x........2x
E........solid.......x........2x
Substitute the E line into the Ksp expression for Mg(OH)2 and solve for x = solubility in mols/L. Convert to g. g = mols x molar mass. This gives you solubility Mg(OH)2 in grams/L. Divide by 10 to convert to 100 mL.