Kevin will rent a car for the weekend. He can choose one of two plans. The first plan has no initial fee but costs
$0.90
per mile driven. The second plan has an initial fee of
$50
and costs an additional
$0.70
per mile driven. How many miles would Kevin need to drive for the two plans to cost the same?
for m miles, you want
0 + 0.90m = 50 + 0.70m
m=110
Let's denote the number of miles driven as x.
For the first plan, the cost would be given by 0.90x.
For the second plan, the cost would be given by 50 + 0.70x.
To find the number of miles x when the two plans cost the same, we can set up the equation:
0.90x = 50 + 0.70x
Now, let's simplify and solve for x:
0.90x - 0.70x = 50
0.20x = 50
x = 50 / 0.20
x = 250
Therefore, Kevin would need to drive 250 miles for the two plans to cost the same.
To find out how many miles Kevin would need to drive for the two plans to cost the same, we need to set up an equation.
Let's denote the number of miles driven as x.
For the first plan (no initial fee), the cost would be $0.90 per mile driven, so the total cost would be 0.9x.
For the second plan (with an initial fee of $50), the cost would be $0.70 per mile driven, plus the initial fee of $50. So the total cost would be 0.7x + 50.
To set up the equation, we equate the two costs:
0.9x = 0.7x + 50
Now, let's solve the equation for x:
0.9x - 0.7x = 50
0.2x = 50
x = 50 / 0.2
x = 250
Therefore, Kevin would need to drive 250 miles for the two plans to cost the same.