How much energy is needed to raise 500 grams of water from 10 degrees Celsius to 40 degrees Celsius?
well what is the specific heat or heat capacity of water in
Joules or Calories (whichever your class is using)per gram (or kilogram or oz or pound) degree centigrade (or Fahrenheit)
anyway call it C
Heat in = C * 500 (40-10)
15000
To calculate the energy needed to raise the temperature of water, you can use the specific heat capacity formula:
Energy = mass * specific heat capacity * temperature change
In this case,
mass = 500 grams (or 0.5 kilograms),
specific heat capacity of water = 4.18 J/g°C, and
temperature change = (40°C - 10°C) = 30°C.
Now we can plug these values into the formula:
Energy = 0.5 kg * 4.18 J/g°C * 30°C
= 62.7 Joules (J)
Therefore, the energy needed to raise 500 grams of water from 10 degrees Celsius to 40 degrees Celsius is 62.7 Joules.
To calculate the energy required to raise the temperature of a substance, we can use the specific heat capacity formula:
Q = m * c * ΔT
Where:
Q = Energy (in joules)
m = Mass of the substance (in grams)
c = Specific heat capacity of the substance (in joules per gram per degree Celsius)
ΔT = Change in temperature (in degrees Celsius)
In this case, the mass of water is 500 grams, the initial temperature is 10 degrees Celsius, and the final temperature is 40 degrees Celsius. The specific heat capacity of water is approximately 4.18 joules per gram per degree Celsius.
Substituting the values into the formula:
Q = 500g * 4.18 (J/g°C) * (40°C - 10°C)
Simplifying:
Q = 500g * 4.18 (J/g°C) * 30°C
Calculating the result:
Q = 62,700 joules
Therefore, approximately 62,700 joules of energy are needed to raise 500 grams of water from 10 degrees Celsius to 40 degrees Celsius.