14.0 grams of potassium hydroxide was dissolved to form 100 centimetre cubeof an aqueous solution. What was the concentration of this solution in mol/decimetre cube.

1.4

Correct! The concentration of the solution is 1.4 mol/dm^3.

To find the concentration of the solution in mol/dm³, we need to calculate the number of moles of potassium hydroxide (KOH) present in the solution.

The molar mass of KOH is:
Potassium (K) = 39.10 g/mol
Oxygen (O) = 16.00 g/mol
Hydrogen (H) = 1.01 g/mol

So, the molar mass of KOH = 39.10 + 16.00 + 1.01 = 56.11 g/mol.

Given that the mass of KOH in the solution is 14.0 g, we can calculate the number of moles:

Number of moles = Mass / Molar mass
= 14.0 g / 56.11 g/mol
= 0.2491 mol

Now, we need to convert the volume from cm³ to dm³. Since 1 dm³ = 1000 cm³, we have:

Volume of solution in dm³ = 100 cm³ / 1000
= 0.1 dm³

Finally, we can calculate the concentration:

Concentration (in mol/dm³) = Number of moles / Volume in dm³
= 0.2491 mol / 0.1 dm³
= 2.491 mol/dm³

Therefore, the concentration of the solution is 2.491 mol/dm³.

M = mols/dm^3 = mols/0.1

mols = grams/molar mass = 14.0/approx 56 = ?
Substitute into M = mols/L and solve for M.