calculus

Find the points on the curve y = 2x^3 + 3x^2 - 12x + 1 where the tangent is horizontal

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asked by Samuel
  1. That means the slope of the tangent is zero. Look for the points where the derivative
    dy/dx = 6x^2 + 6x -12 = 0

    x^2 +x -2 = 0
    (x+2)(x-1) - 0

    x - -2 or +1.

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    posted by drwls

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