What is the pKa for the acid HA if a solution of 0.65 M HA and 0.85 M NaA has a pH of 4.75?

~~~I know you find the ph by doing -log of pka; how do you do the reverse when you have molarity? I am completely lost. :-(

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  1. You're trying to make this a hard problem when it isn't.
    This is a buffered solution, use the Henderson-Hasselbalch equation.
    pH = pKa + log (base)/(acid)
    They give the pH, base is 0.85 and acid is 0.65. Substitute and solve for pKa.

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