What mass of ammonium chloride must be decomposed to prepare 134 grams of ammonia (NH3). Hydrochloric acid will also be produced.
NH4Cl ==> NH3 + HCl
mols NH3 produced = grams/molar mass = 134/17 = approx 8 but you need a better answer.
Using the coefficients in the balanced equation A(everything is 1:1) convert mols NH3 to mols NH4Cl.
Now convert mols NH4Cl to grams. g NH4Cl = mols NH4Cl x molar mass NH4Cl
Post your work if you get stuck.
To determine the mass of ammonium chloride required to produce a certain amount of ammonia (NH3), we need to first understand the chemical equation for the decomposition of ammonium chloride.
The balanced equation is:
NH4Cl → NH3 + HCl
From this equation, we can see that 1 mole of NH4Cl decomposes to produce 1 mole of NH3 and 1 mole of HCl.
Now we have the following information:
- The molar mass of NH3 is 17.03 g/mol.
- We want to produce 134 grams of NH3.
Using the molar mass of NH3, we can calculate the number of moles of NH3:
Number of moles = mass / molar mass
Number of moles of NH3 = 134 g / 17.03 g/mol ≈ 7.87 moles
Since the ratio between NH4Cl and NH3 is 1:1, we know that the number of moles of NH4Cl required is also 7.87 moles.
Finally, we can calculate the mass of NH4Cl:
Mass of NH4Cl = number of moles * molar mass of NH4Cl
Mass of NH4Cl = 7.87 moles * (14.01 g/mol + 1.01 g/mol + 35.45 g/mol)
Simplifying, the molar mass of NH4Cl is 53.47 g/mol (14.01 g/mol + 1.01 g/mol + 35.45 g/mol):
Mass of NH4Cl = 7.87 moles * 53.47 g/mol
Mass of NH4Cl ≈ 420.95 g
Therefore, approximately 420.95 grams of ammonium chloride must be decomposed to produce 134 grams of ammonia (NH3).