Kim invested a total of $1500 in two accounts. One account paid 2% annual interest and the other paid 4% annual interest. After one year, Kim earned $44 in interest. How much did she invest in each account?

amount invested in the 2% account --- x

amount invested in the 4% account = 1500-x

solve for x

.02x + .04(1500-x) = 44

-800

To solve this problem, we can use a system of equations. Let's assume Kim invested x dollars in the account paying 2% interest and y dollars in the account paying 4% interest.

The interest earned from the first account, at 2%, can be calculated by multiplying the amount invested in that account (x) by the interest rate (0.02):
Interest from first account = 0.02x

Similarly, the interest earned from the second account, at 4%, can be calculated by multiplying the amount invested in that account (y) by the interest rate (0.04):
Interest from second account = 0.04y

According to the given information, the total interest earned after one year is $44. Therefore, we can set up the first equation:
0.02x + 0.04y = 44

Additionally, we know that Kim invested a total of $1500, so the sum of the amounts invested in both accounts equals $1500. This gives us the second equation:
x + y = 1500

Now we have a system of equations:
0.02x + 0.04y = 44
x + y = 1500

To solve this system of equations, we can use substitution or elimination. Let's use elimination to solve for the values of x and y.

Multiply the first equation by 100 to get rid of the decimals:
2x + 4y = 4400

Now, multiply the second equation by 2:
2(x + y) = 2 * 1500
2x + 2y = 3000

Now we have a new system of equations:
2x + 4y = 4400
2x + 2y = 3000

Subtract the second equation from the first to eliminate x:
(2x + 4y) - (2x + 2y) = 4400 - 3000
2y = 1400
y = 700

Substitute the value of y into the second equation to solve for x:
x + 700 = 1500
x = 1500 - 700
x = 800

Therefore, Kim invested $800 in the account paying 2% interest and $700 in the account paying 4% interest.