How many moles of compound are present in 17g of Fe2O3?


I think I know how to do this, so if someone can show me so I can check my work against it. My answer was .106 moles of Fe2O3.

Why don't you show how you did it ans let us check your work.

Well, If Fe atomic mass is 55.85 and O is 16, then multipy 55.85 by two and 16 by 3 and get 159.7 g/mol. Then divide 17g by 159.7 g/mol and get .106 moles.

You are absolutely correct. Good work.

To calculate the number of moles of a compound, you need to use the compound's molar mass.

1. Start by finding the molar mass of Fe2O3.

The molar mass of Fe2O3 can be calculated by adding up the atomic masses of its constituent elements. The atomic mass of iron (Fe) is approximately 55.85 g/mol, and the atomic mass of oxygen (O) is approximately 16.00 g/mol.

So, the molar mass of Fe2O3 is:
(2 * atomic mass of Fe) + (3 * atomic mass of O) = (2 * 55.85 g/mol) + (3 * 16.00 g/mol) = 159.70 g/mol

2. Use the molar mass to convert the given mass of the compound into moles.

To convert grams to moles, divide the given mass by the molar mass:
17 g / 159.70 g/mol = 0.1065 mol (rounded to four decimal places)

So, the correct answer is approximately 0.1065 moles of Fe2O3, which agrees with your answer of 0.106 moles.