Find the quotient of the quantity negative 36 times x to the 3rd power minus 6 times x to the 2nd power plus 12 times x all over negative 6 times x.

−36x3 − 6x2 − 2
−6x2 + x − 2
6x2 − x + 2
6x2 + x − 2

pls help me

(-36x³-6x²+12x) / (-6x)

now factor

-6x (6x²+x-2) / (-6x)

-6x cancels out

6x²+x-2

To find the quotient of the expression: (-36x^3 - 6x^2 + 12x) / (-6x), you need to divide the numerator by the denominator.

First, let's simplify the numerator:
(-36x^3 - 6x^2 + 12x)

To simplify this expression, we can factor out the common factor of x from each term:
x * (-36x^2 - 6x + 12)

Now we can simplify further by dividing each term by -6x:
-6x * (6x^2 + x - 2)

Therefore, the simplified expression is (-6x)(6x^2 + x - 2).

So, the correct quotient is 6x^2 + x - 2. Option "3. 6x^2 + x - 2" is the correct answer.