Is it easier to evaluate n^0 w^0 for n=-2 and w=3 by simplifying first or by substitute first ? explain
makes no difference,
you can do both ways in your head,
since (anything)^0 = 1
you will get 1
To evaluate n^0 w^0, where n=-2 and w=3, we can simplify or substitute the values first and then evaluate. Let's break down both approaches:
1. Simplifying First:
In this approach, we start by simplifying the expression n^0 w^0 using the rule that any number raised to the power of 0 is equal to 1.
n^0 = 1, since (-2)^0 = 1
w^0 = 1, since (3)^0 = 1
Multiplying these results, we get 1 * 1 = 1. Therefore, n^0 w^0 = 1.
2. Substituting First:
In this approach, we substitute the given values of n and w into the expression n^0 w^0 and then evaluate.
Substituting the values, we get:
(-2)^0 (3)^0
As mentioned earlier, any number raised to the power of 0 is equal to 1. Therefore, both (-2)^0 and (3)^0 are equal to 1.
Hence, when we multiply the two results, we have 1 * 1 = 1. Therefore, n^0 w^0 = 1.
Comparing the two methods:
Both approaches lead to the same result, which is 1. However, the simplifying first approach involves applying the power of 0 rule, which is a general mathematical concept. On the other hand, the substituting first approach involves directly substituting the given values and then applying the power of 0 rule.
In this specific situation, both approaches are equally straightforward and yield the same result. Therefore, both methods can be considered equally easy.