A ball is attached to a center post by a string that is 0.382 m long. The ball is moving in a circle on a frictionless table top at a speed of 1.28 m/s with a radius of 0.382 m. What is the centripetal acceleration of the ball?
a(c) = v²/R=
=(1.28)²/0.382 = 4.29 m²/s
To find the centripetal acceleration of the ball, you can use the formula:
Centripetal acceleration (ac) = (v^2) / r
where:
- ac is the centripetal acceleration
- v is the velocity of the ball
- r is the radius of the circle
Given:
v = 1.28 m/s
r = 0.382 m
Substituting these values into the formula, we get:
ac = (1.28^2) / 0.382
Calculating this expression, we find that the centripetal acceleration of the ball is approximately 4.28 m/s^2.
To find the centripetal acceleration of the ball, we can use the formula:
Centripetal acceleration (a) = (v^2) / r
Where:
- v is the velocity of the ball
- r is the radius of the circular path
We are given:
- v = 1.28 m/s
- r = 0.382 m
Substituting the given values into the formula, we get:
a = (1.28^2) / 0.382
a = 1.6384 / 0.382
a ≈ 4.28 m/s^2
Therefore, the centripetal acceleration of the ball is approximately 4.28 m/s^2.