A 5 kg block is being pulled on a frictionless surface by a string at an angle of 30o to the horizontal. The tension in the string is 30 N. What is the total work done on the block as it moves a distance of 10 m?

Thank you!

what is the difference between potential energya nd electric potential

To find the total work done on the block, we can first calculate the work done by the tension force and then calculate the work done by the gravitational force.

1. Calculating the work done by the tension force:
The work done by a force can be calculated using the formula: work = force * distance * cos(theta), where theta is the angle between the force and the displacement.

In this case, the tension force and the displacement are in the same direction (since there is no friction to oppose the motion), so the angle between them is 0 degrees.

Therefore, the work done by the tension force is given by: work = 30 N * 10 m * cos(0) = 300 J.

2. Calculating the work done by the gravitational force:
When an object moves parallel to the surface, the work done by the gravitational force is zero. This is because the displacement and the force are perpendicular to each other.

Therefore, the work done by the gravitational force is zero.

3. Calculating the total work done:
The total work done is the sum of the work done by the tension force and the work done by the gravitational force.

Total work done = Work done by tension force + Work done by gravitational force
= 300 J + 0 J
= 300 J.

Therefore, the total work done on the block as it moves a distance of 10 m is 300 Joules.