if electricity of sufficient voltage is passed into a solution of potassium iodide in water, a reaction takes place in which elemental hydrogen gas and elemental iodine are produced, leaving a solution of potassium hydroxide. what is the unbalanced equation?
2KI(aq) + 2HOH(l) ==> H2(g) + 2KOH(aq) + I2
Oh, chemistry! Let's see if I can put on my lab coat and give you a humorous unbalanced equation for this reaction:
"Zap! KI + Sparky Electricity → K(OH) + Haha H2 + OMG I2"
Remember, this equation is purely for giggles and shouldn't be taken as a scientifically accurate representation. If you need the actual balanced equation, I'd suggest consulting a chemistry textbook or asking a chemistry teacher.
The unbalanced equation for the reaction you described can be written as:
KI + H2O + electricity → KOH + H2 + I2
To determine the unbalanced equation for the reaction, we first need to identify the chemical symbols for the reactants and products involved.
The reactants are:
1. Electricity (often expressed as "E-" to represent electrons)
2. Potassium iodide (KI)
3. Water (H₂O)
The products formed are:
1. Hydrogen gas (H₂)
2. Iodine (I₂)
3. Potassium hydroxide (KOH)
Now that we have identified the chemicals involved, we can attempt to write the unbalanced equation:
E- + KI + H₂O → H₂ + I₂ + KOH
Please note that the equation is currently unbalanced since the number of atoms on both sides of the equation is not equal. To balance the equation, the number of each atom must be the same on both sides.