How do i make a table of value for a quadratic relation? How do i know what x-values to use in the table?
Can someone show me using this set of equations as an example.
y= x^2
y= (x-2)^2
y= (x-4)^2
just pick values for x and calculate values for y. Same as for any relation. Take advantage of symmetry, and you can save half your work.
x x^2
0 0
1 1
2 4
3 9
4 16
and the same values for x=-1,-2,-3,-4,...
Now watch what happens for the next one.
x (x-2)^2
2 0
3 1
4 4
5 9
6 16
and the same values for x= 1,0,-1,-2,-3,...
and so on
where you give a range of value?...or do you have a table already? can i see it in row if you have
wow learning new thing everyday here God bless you steve
To make a table of values for a quadratic relation, you need to choose different x-values and then calculate the corresponding y-values using the given equations. Here's how you can do it for the three quadratic equations you provided:
1. For the equation y = x^2:
- Choose a set of x-values. Let's say -2, -1, 0, 1, and 2.
- Calculate the corresponding y-values by substituting the chosen x-values into the equation:
- For x = -2, y = (-2)^2 = 4
- For x = -1, y = (-1)^2 = 1
- For x = 0, y = (0)^2 = 0
- For x = 1, y = (1)^2 = 1
- For x = 2, y = (2)^2 = 4
- Create a table with two columns: one for x and another for y.
Table 1: y = x^2
| x | y |
|-----|-----|
| -2 | 4 |
| -1 | 1 |
| 0 | 0 |
| 1 | 1 |
| 2 | 4 |
2. For the equation y = (x-2)^2:
- Choose a set of x-values. Let's use -1, 0, 1, 2, and 3.
- Substitute each chosen x-value into the equation to find the corresponding y-value:
- For x = -1, y = (-1-2)^2 = (-3)^2 = 9
- For x = 0, y = (0-2)^2 = (-2)^2 = 4
- For x = 1, y = (1-2)^2 = (-1)^2 = 1
- For x = 2, y = (2-2)^2 = (0)^2 = 0
- For x = 3, y = (3-2)^2 = (1)^2 = 1
- Create a table with two columns: one for x and another for y.
Table 2: y = (x-2)^2
| x | y |
|-----|-----|
| -1 | 9 |
| 0 | 4 |
| 1 | 1 |
| 2 | 0 |
| 3 | 1 |
3. For the equation y = (x-4)^2:
- Choose a set of x-values. Let's take -2, -1, 0, 1, and 2.
- Substitute each chosen x-value into the equation to find the corresponding y-value:
- For x = -2, y = (-2-4)^2 = (-6)^2 = 36
- For x = -1, y = (-1-4)^2 = (-5)^2 = 25
- For x = 0, y = (0-4)^2 = (-4)^2 = 16
- For x = 1, y = (1-4)^2 = (-3)^2 = 9
- For x = 2, y = (2-4)^2 = (-2)^2 = 4
- Create a table with two columns: one for x and another for y.
Table 3: y = (x-4)^2
| x | y |
|-----|-----|
| -2 | 36 |
| -1 | 25 |
| 0 | 16 |
| 1 | 9 |
| 2 | 4 |
By following the steps above, you can create tables of values for quadratic relations using different x-values and their corresponding y-values, as calculated from the given equations.