A game consists of drawing a number from 1-20. A player wins if the number drawn is either a prime number or a perfect square. What is the probability of winning the game?
1,2,3,4,5,6,7,8,9,10,11,12,13,14,14,16,17,18,19,20
now bring out the prime number
and that of perfect square
and don,t forget the total outcome is 20
now
pr(P or E)=additional
pr(prime number or perfect number)=addition
so 55% is the answer @ collins?
thanks for the help though
the prime number from 1-20 is 8
and
perfect square is 4
8/20+4/20=12/20
now reduce to the lowest term
To calculate the probability of winning the game, we need to find the total number of favorable outcomes (numbers drawn that are either prime or perfect squares) and divide it by the total number of possible outcomes (all numbers from 1 to 20).
Step 1: Find the favorable outcomes:
- Prime numbers between 1 and 20: 2, 3, 5, 7, 11, 13, 17, 19 (8 numbers)
- Perfect squares between 1 and 20: 1, 4, 9, 16 (4 numbers)
So, there are a total of 8 prime numbers and 4 perfect squares, making a total of 12 favorable outcomes.
Step 2: Find the total number of possible outcomes:
We are drawing a number from 1 to 20, so there are a total of 20 possible outcomes.
Step 3: Calculate the probability:
Now we can calculate the probability of winning the game by dividing the number of favorable outcomes by the total number of possible outcomes:
Probability of winning = Favorable outcomes / Total outcomes
= 12 / 20
= 0.6
So, the probability of winning the game is 0.6 or 60%.