calculate the molarity of solution cacl2 . if on the chemical analysis . it is found that 200 ml of solution contains 3 into 10 raise the power 22 cl- ions
You need to find the caps key and use it. 5E3 means 5 x 10^3 = 5000 = 5 times 10 to the third power.
1 mol contains 6.02E23 ions.
3E22/6.02E23 = approx 0.05 mol Cl^- ions.
mols CaCl2 = 1/2 that since 1 mol CaCl2 contains 2 mols CaCl2.
Then M = mols/L = approx 0.05 mols/0.200 L = ?
To calculate the molarity (M) of a solution, you need to know the number of moles of solute and the volume of the solution.
In this case, you are given the volume of the solution (200 mL) and the number of chloride ions (3 × 10^22 Cl- ions). To find the number of moles of chloride ions, you need to use Avogadro's number, which states that there are 6.022 × 10^23 particles (atoms, molecules, or ions) in one mole of a substance.
Step 1: Convert the given volume of the solution from milliliters (mL) to liters (L).
200 mL = 200/1000 = 0.2 L
Step 2: Calculate the number of moles of chloride ions using the given number of chloride ions and Avogadro's number.
Number of moles of Cl- ions = (3 × 10^22 ions) / (6.022 × 10^23 ions/mol)
Step 3: Calculate the molarity of the solution by dividing the number of moles of solute by the volume of the solution in liters.
Molarity (M) = (Number of moles of solute) / (Volume of solution in liters)
Substituting the values:
M = (3 × 10^22 ions) / (6.022 × 10^23 ions/mol) / 0.2 L
Simplifying the expression:
M = (3 × 10^22 ions) / (6.022 × 10^23 ions/mol × 0.2 L)
Now, you can calculate the molarity using a calculator or by further simplifying the expression.
To calculate the molarity of the CaCl2 solution, we need to know the number of moles of CaCl2 and the volume of the solution.
First, let's find the number of moles of Cl- ions in 200 mL of solution:
3 x 10^22 Cl- ions = moles of Cl-
Next, we need to convert the volume of the solution into liters, as molarity is given in moles per liter:
200 mL * (1 L / 1000 mL) = 0.2 L
Now, we can calculate the molarity (M) of the CaCl2 solution using the equation:
Molarity (M) = moles of solute / volume of solution (in liters)
Molarity (M) = (moles of Cl-) / (volume of solution in liters)
Molarity (M) = (3 x 10^22) / 0.2
Molarity (M) = 1.5 x 10^23 mol/L
Therefore, the molarity of the CaCl2 solution is 1.5 x 10^23 mol/L.