How do you write out and finish the equation when:1: iron(lll) reacts with calcium metal: 2: Magnesium sulfide reacts with calcium phosphate
Fe^3+ + Ca>> calcium is more active than Fe, so Ca will give up electrons to a Fe ion
2Fe^3+ + 3Ca>> 3Ca^2+ + 2Fe
MgS+ Ca3(PO4)2 ok, pretending it would react, which I can't imagine,
products would be
Mg3(PO4)2 + CaS
To write out and finish the equations for these chemical reactions, we need to balance the chemical equation by ensuring that the number of atoms of each element is the same on both sides of the equation.
1. Iron(III) reacts with calcium metal:
Step 1: Identify the chemical formulas of the reactants and products.
The chemical formula for iron(III) is Fe3+ (III indicates the charge of +3), and the chemical formula for calcium is Ca.
Step 2: Write out the unbalanced equation.
Fe3+ + Ca → ?
Step 3: Balance the equation by adding coefficients.
To balance the equation, we need to make sure that the number of atoms of each element is the same on both sides.
Fe3+ + 3Ca → Fe + 3Ca2+
The balanced equation is:
2Fe3+ + 6Ca → 2Fe + 6Ca2+
2. Magnesium sulfide reacts with calcium phosphate:
Step 1: Identify the chemical formulas of the reactants and products.
The chemical formula for magnesium sulfide is MgS, and the chemical formula for calcium phosphate is Ca3(PO4)2.
Step 2: Write out the unbalanced equation.
MgS + Ca3(PO4)2 → ?
Step 3: Balance the equation by adding coefficients.
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides.
MgS + Ca3(PO4)2 → 3Mg3(PO4)2 + 2CaS
The balanced equation is:
3MgS + Ca3(PO4)2 → 3Mg3(PO4)2 + CaS
By following these steps, we can write out and finish the equations for chemical reactions.