# maths

To fill a swimming pool two pipes are to be used.If the pipe of larger diameter I'd used for 4 hours and the pipe of smaller diameter for 9 hours only half the pool can be filled .Find ,how long it would take for each pipe to fill the tank separately, if the pipe of smaller diameter takes 10 hours more than the pipe of larger diameter to fill the pool.

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1. If the faster pipe takes x hours, then we have to look at how much of the pool is filled each hour.

4/x + 9/(x+10) = 1/2

Now solve for x, and then get x+10.

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2. Very simple
First do 4\x+9\x+10
And get x

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3. potty

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4. got to hell and die there and clean your dead body!!!!!!!!!!!!!!!!!!!.
before dying please do potty and then go to hell..............

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5. Just

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6. let pipe of larger diameter fills in hrs= x
In 1hr level=1/x
pipe of smaller diamter fills in hrs= x+10
A.T.Q
4/x+9/x+10=1/2
4(x+10)+9x/x(x+10)=1/2
4x+40+9x/x^2+10x=1/2 (x^2=square of x)
x^2+10x=80+26x
x^2-16x-80=0
a=1 b=-16 c=-80
b^2-4ac= (-16)^2-4(1)(-80)
= 256+320
= 576=24
x=-(-16)+24/2 x=-(-16)-24
x=40/2 x=-8/2
x=20 x=-4
hence,larger diamtere takes 20 hrs and smaller diameter takes x+10=20+10=30

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7. Larger in 20 hrs and smaller in 30 hrs

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8. Larger 20 hrs and smaller 30 hrs

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