what is the maximum amount of NO2 which could be formed from 14.75 g of NO and 1.28 g of O2?
Answer in units of mol.
i believe its 2 NO + O2 -> 2 NO2
but I'm not sure
and i don't know what to do
when i tried with stoichiometry i got .4916
but when i got told its the wrong answer, so how??
for each mole of NO, one gets one mole of NO2
moles NO=14.75/(14+16)
moles NO2 = above.
grams NO2=molesNO2*molemassNO2