A rectangular lap pool has a constant depth. The length of the pool is 9 times the width, and the surface area of the water is 81 square feet. What are the dimensions of the pool? Include units.

width --- x

length ---9x

x(9x) = 81
x^2 = 9
x = 3

the pool is 3 ft by 27 ft.

(I bet whoever swims in that pool is fantastic at flip-turns )

To find the dimensions of the lap pool, we can set up an equation using the given information.

Let's assume that the width of the pool is represented by "w" feet.

Now, the length of the pool is given as 9 times the width, which means the length is 9w feet.

Since the pool has a constant depth, we don't need to consider it in this question.

The equation for the surface area of a rectangle is length times width. In this case, the surface area is given as 81 square feet.

So, the equation becomes:

(9w) * w = 81

To solve for the width, we can simplify the equation:

9w^2 = 81

Divide both sides of the equation by 9:

w^2 = 9

Taking the square root of both sides, we get:

w = 3

Since the width is 3 feet, we can find the length by multiplying it by 9:

Length = 9 * 3 = 27 feet

Therefore, the dimensions of the lap pool are 27 feet in length and 3 feet in width.