IF the sum of areas of two squares is 610msquare and the difference of their perimeters is 32m,then find the lengths of their sides?
If the perimeters differ by 32, the sides differ by 8.
s^2 + (s+8)^2 = 610
Now just find s and s+8.
s^2 + (s+8)^2 = 610
Now just find s and s+8.