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Mathematics
Algebra
Logarithms
find the lograihm of 1728 to the base 2root3
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find the logarithm off 1782 to the base 2root3
Top answer:
2 sqrt3 = 3.4641 3.4641^x = 1782 x log 3.4641 = log 1782 x = 6.0248
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Find four geometric means between 4096 and 972.
an=a1*r^n-1 a6=972*r^6-1 4096=972r^5 4.2=r^5 1.3 972(1.3)=1296 1296(1.3)=1728
Top answer:
in your sequence term<sub>1</sub> = 4096 so a=4096 and term<sub>6</sub> = ar^5 = 972 then r^5 =
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Log 1728 to the base √3
Top answer:
since √3 = 3^(1/2) log<sub><sub>√3</sub></sub>1728 = 2log<sub><sub>3</sub></sub>1728 now, 1728 =
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Express 1728 and 2025 in terms of their prime factors. Hence evaluate ³√1728/√2025
Top answer:
1728 = 12^3 = 2^6 3^3 2025 = 45^2 = 3^4 5^2 so, ...
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Express 1728 and 2025 in terms of their prime factors. Hence evaluate:
((1728)^1/3))/sq(2025)
Top answer:
1728 = 12^3 2025 = 45^2 You can reduce those to prime factors if you want, but it's pretty clear
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find derivative of (8sqrt(x)+(9/2root3(x)))^2
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You have not supplied sufficient parentheses to render the expression unambiguous, that probably
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F2088nd the next three terms of the sequence. -2, -12, -72, 432.
Possibilities are: 1. -1728 -6912 -27,648 2. -1728 -10,368
Top answer:
I strongly suspect they mean: -2, -12, -72, -432 If my suspicion is correct you have a geometric
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The sum of the first three term in a G.P is 38. Their product is 1728. Find the values of the three terms.
Top answer:
a(1+r+r^2) = 38 a*ar*ar^2 = 1728 now divide to get r^3/(1+r+r^2) = 1728/38 now solve for r, then get
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Find exact value of each expression
sec^-1 (2root3) / 5 I have no idea what to do to make that into a value. I know that sec^-1
Top answer:
This is a trick question. 2√3/5 = 0.69 but sec(x) is never less than 1.
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From the set A={3,root2,2root3,root9,root7},a number is selected at random.find the probability that is a rational number.
Top answer:
A = { 3, √2, 2√3, √9, √7} , but √9 = 3 which is rational, so you have 2 rationals out of
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