using the equation
c3h5+5o2=3co2+4h2o, calculate the mass of c3h8 that can produce 100g of h2o
C3H8 + 5O2 = 3CO2 + 4H2O
To calculate the mass of C3H8 that can produce 100g of H2O using the given equation, we need to follow a few steps:
Step 1: Write the balanced chemical equation.
The given equation is not balanced. We need to balance it first:
C3H8 + 5O2 → 3CO2 + 4H2O
Step 2: Determine the molar masses.
- The molar mass of C3H8 (propane) = 3(12.01 g/mol) + 8(1.01 g/mol) = 44.11 g/mol
- The molar mass of H2O = 2(1.01 g/mol) + 16.00 g/mol = 18.02 g/mol
Step 3: Calculate the number of moles of H2O produced.
Given mass of H2O = 100 g
Number of moles of H2O = mass/molar mass = 100 g / 18.02 g/mol ≈ 5.55 mol
Step 4: Use the coefficients in the balanced equation to determine the number of moles of C3H8.
From the balanced equation: 4 moles of H2O correspond to 1 mole of C3H8.
Therefore, number of moles of C3H8 = (5.55 mol H2O) / (4 mol H2O/1 mol C3H8) = 1.39 mol C3H8
Step 5: Calculate the mass of C3H8.
Mass of C3H8 = number of moles × molar mass = 1.39 mol × 44.11 g/mol ≈ 61.27 g
Therefore, approximately 61.27 grams of C3H8 (propane) can produce 100 grams of H2O.