Sodium phosphate, Na3PO4, reacts with HCl to form H3PO4 and NaCl. How many liters of 0.1 M HCl are required to react with 0.1 mole of sodium phosphate?
You need to start with a balanced equation.
So balance:
Na3PO4 + HCl = H3PO4 + NaCl
Na3PO4 + 3HCL = H3PO4 +3NaCl
Oh boy, chemistry questions! Well, it seems like we have a sodium phosphate party going on here. So, let's break it down.
We know that 1 mole of sodium phosphate reacts with 3 moles of HCl, forming 1 mole of H3PO4 and 3 moles of NaCl. So the mole ratio is 1:3.
Since we have 0.1 mole of sodium phosphate, we need 0.3 moles of HCl to react with it (0.1 mole x 3 moles HCl/1 mole Na3PO4).
Now, we have the mole amount we need. But to figure out the volume of the 0.1 M HCl solution, we need to use the formula: moles = concentration x volume.
0.3 moles = 0.1 M x volume
Volume = 0.3/0.1 = 3 liters
So, you'll need 3 liters of that 0.1 M HCl solution to have a proper reaction with your 0.1 mole of sodium phosphate. I hope that puts a smile on your face!
Remember, though, this is just a theoretical calculation. In reality, the reaction might not be 100% complete, so you may need a little more HCl to ensure complete reaction.
To find the number of liters of 0.1 M HCl required to react with 0.1 mole of sodium phosphate (Na3PO4), we need to use the balanced chemical equation and perform stoichiometry calculations.
Let's start by writing the balanced chemical equation for the reaction:
3 Na3PO4 + 6 HCl → 3 H3PO4 + 6 NaCl
From the balanced equation, we can see that 3 moles of sodium phosphate react with 6 moles of HCl.
Now, calculate the number of moles of HCl needed. Since the molar ratio between Na3PO4 and HCl is 3:6, we can say that for 0.1 moles of Na3PO4, we need (0.1 moles HCl) x (6 moles HCl / 3 moles Na3PO4) = 0.2 moles of HCl.
Next, we need to find the volume of 0.1 M HCl solution needed. The concentration of HCl is given as 0.1 M, which means that there are 0.1 moles of HCl in 1 liter of solution.
Therefore, the volume of 0.1 M HCl solution needed can be calculated as (0.2 moles HCl) / (0.1 moles HCl per liter) = 2 liters.
So, 2 liters of 0.1 M HCl are required to react with 0.1 mole of sodium phosphate (Na3PO4).