A v vs t graph is drawn for a ball moving in one direction. The graph starts at the origin and at t=5s the acceleration of the ball is zero. We know that at t=5s,
a) the curve is not crossing the time axis
b) the velocity of the ball is not changing
c) the slope of the curve is nonzero
d) the curve is at v=0, t=0
I assume you know that when the acceleration is zero, the velocity is not changing
i think b is correct.. but what makes "a" incorrect?
When t=5, you are not crossing the velocity (vertical) axis. If you were crossing the time axis, the velocity would be zero.
It is not impossible for velocity and acceleration to be zero at the same time, asymptotically. But if you are crossing the time axis, velocity must be changing with time. If acceleration is zero, you are not crossing the time line. So I agree (a) is OK also
but there is only one correct answer
Not this time. Flip a coin
Well, it seems like this graph is throwing us a curveball! Let me break it down for you:
a) If the acceleration of the ball is zero at t=5s, that means the curve on the graph is going to be flat at that point. So, it won't be crossing the time axis. That rules out option a.
b) Since the acceleration is zero, that means there's no change in the velocity of the ball. So, option b is incorrect.
c) Now, about the slope of the curve. If the curve is flat at t=5s, that means the slope of the curve is zero. So, option c is also not the right answer.
d) Finally, let's talk about the curve being at v=0, t=0. Well, the graph starts at the origin, which means at t=0, the ball is at rest. So, option d is out of the picture too.
After all that analyzing, we can conclude that the correct answer is none of the above! Keep those graphing skills sharp, my friend!
To determine the correct statement at t=5s on the v vs t graph for a ball moving in one direction, we need to understand the information provided.
The v vs t graph represents the velocity (v) of the ball as a function of time (t). Here are the given details:
- The graph starts at the origin (v=0, t=0).
- At t=5s, the acceleration of the ball is zero.
Let's analyze each statement to see which one is true:
a) The curve is not crossing the time axis:
Crossing the time axis would imply that the velocity becomes zero at some point. Since the graph starts at the origin (v=0, t=0) and nothing suggests a change in the velocity around t=5s, it is possible for the curve to cross or not cross the time axis. This statement is inconclusive.
b) The velocity of the ball is not changing:
The graph shows the velocity of the ball as a function of time. If the velocity is not changing, it means that the slope of the curve is zero. However, we know that the acceleration is zero at t=5s, not the velocity. Therefore, this statement is incorrect.
c) The slope of the curve is nonzero:
When the acceleration of the ball is zero, it means that the slope of the v vs t curve is constant. If the acceleration were non-zero, it would indicate a changing slope. Since the acceleration is zero at t=5s, the slope of the curve remains constant. Thus, this statement is true.
d) The curve is at v=0, t=0:
Based on the given information, there is no indication that the curve is at v=0, t=0. The only information provided is that at t=5s, the acceleration is zero. Therefore, this statement is incorrect.
In conclusion, the correct statement at t=5s on the v vs t graph for a ball moving in one direction is:
c) The slope of the curve is nonzero.