At their closest approach, Venus and Earth are 4.2x10^10m apart. The mass of Venus is 4.87x10^24kg, the mass of Earth is 5.97x10^24kg, and G=6.67x10^-11Nm2/kg2. What is the force exerted by Venus on Earth at that point?
nvm i found the answer
The equation is F = (G X M1 x M2) divided by d^2
(6.67E-11 x 4.87E24 x 5.97E24) / (4.2E10)^2 = 1.1 E18 N
m1=4.87x1o^24kg m2=5.97x10^24kg r=4.2x10^10m G=6.67x1o^-11 f=? f=Gm1m2/r^2 f=(6.67x10^-11x4.87x1o^24x5.97x10^24)/(4.2x10^10)^2 f=1.1x10^18N
To find the force exerted by Venus on Earth, we can use Newton's law of universal gravitation:
F = (G * m1 * m2) / r^2
Where:
F is the force between the two objects (Venus and Earth)
G is the gravitational constant (6.67x10^-11 Nm^2/kg^2)
m1 is the mass of Venus (4.87x10^24 kg)
m2 is the mass of Earth (5.97x10^24 kg)
r is the distance between the centers of the two objects (4.2x10^10 m)
Substituting the given values into the equation, we have:
F = (6.67x10^-11 Nm^2/kg^2 * 4.87x10^24 kg * 5.97x10^24 kg) / (4.2x10^10 m)^2
Now, let's calculate the force:
F = (6.67x10^-11 Nm^2/kg^2 * 4.87x10^24 kg * 5.97x10^24 kg) / (4.2x10^10 m)^2
F = 1.94x10^20 N
Therefore, the force exerted by Venus on Earth at their closest approach is approximately 1.94x10^20 N.