Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine.
CCl4(g) + 1/2O2(g) COCl2(g) + Cl2(g), Kc = 4.4 × 109 at 1,000 K
Calculate Kc for the reaction 2CCl4(g) + O2(g) 2COCl2(g) + 2Cl2(g).
To calculate Kc for the reaction 2CCl4(g) + O2(g) 2COCl2(g) + 2Cl2(g), you need to use the equilibrium constant expression based on the stoichiometry of the balanced equation.
The equilibrium constant expression is given as:
Kc = [COCl2]^2 * [Cl2]^2 / ([CCl4]^2 * [O2])
Now, we know that Kc for the reaction CCl4(g) + 1/2O2(g) COCl2(g) + Cl2(g) is 4.4 × 10^9 at 1000 K.
However, to use this value to calculate Kc for the new reaction, you first need to adjust the stoichiometry of the given equation to match the desired reaction.
Notice that by multiplying the given equation by 2, you obtain two COCl2(g) and two Cl2(g). Therefore, you need to square the equilibrium constant to account for the change in stoichiometry.
Now, you can substitute the values into the Kc expression:
Kc = (4.4 × 10^9)^2
Calculating the square of 4.4 × 10^9, we get:
Kc ≈ 1.94 × 10^19
Therefore, the value of Kc for the reaction 2CCl4(g) + O2(g) 2COCl2(g) + 2Cl2(g) is approximately 1.94 × 10^19.