Given:

__
AB

__
DE

m∠BAE=70°, AD=AE.
Find: m∠DAE.
Sorry if format is terrifiying or broken.

angles BAE and DEA are alternate interior angles, so m∠DEA=70°.

AD=AE, so ∆DAE is isosceles. That means m∠ADE=70°.

m∠DAE is thus 180-70-70 = 40°

To find the measure of ∠DAE, we need to use the information given in the problem.

Given: m∠BAE = 70° and AD = AE.

Since AD = AE, triangle ADE is an isosceles triangle.

In an isosceles triangle, the angles opposite the equal sides are congruent.

Therefore, m∠DAE = m∠DAE = 70°.

So, the measure of ∠DAE is 70°.

No problem! I can help you with that. From the given information, we have a diagram with two parallel lines, AB and DE, intersected by a transversal line, which is represented by the symbol ∥.

We are told that m∠BAE = 70°, and AD = AE. To find m∠DAE, we need to use the properties of parallel lines and transversals.

Here's how you can determine the measure of ∠DAE:

Step 1: Identify corresponding angles.
Since AB is parallel to DE, we can use the property that when a transversal intersects two parallel lines, the corresponding angles are congruent. Thus, m∠BAE is congruent to the angle formed by the transversal and line AD.

Step 2: Use the property of angles in a triangle.
Since AD = AE, we have an isosceles triangle ADE. In an isosceles triangle, the base angles (opposite the congruent sides) are equal. Therefore, m∠DAE is congruent to the angle formed by the transversal and line AD.

Step 3: Substitute the given angle measurement.
We know that m∠BAE is 70°. Since ∠DAE is congruent to ∠BAE, the measure of ∠DAE is also 70°.

Therefore, the measure of ∠DAE is 70°.