Algebra 1

so im not that good with word problems so... here it goes.

Nadine has 7 more nickles than Delano has dimes. If Delano gives Nadine 4 of his dimes, then Delano will have the same amountof money as Nadine. How much money do they have together, assuming Nadine only has nickles and Delano only has dimes?

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  1. dimes = d
    nickles = (d+7)
    then later
    (d-4)(.1) = (d+7)(.05)+4(.1)

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    posted by Damon
  2. would that be the same as
    .05(d+7)=(d-4).1 ?

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    posted by Bridget
  3. no, you need to credit Nadine with 4 dimes (4)(.1)

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    posted by Damon
  4. oooh!!! ok, thank you!!! so then i would get
    .1d - .4 = .05d + .35 + .4
    .1d - .4 = .05d + .75
    .05d - .4 = .75
    .05d = 1.15
    d = 23
    right???

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    posted by Bridget
  5. looks good

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    posted by Damon
  6. ok, thank you sooo much!!! :)

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    posted by Bridget
  7. -3y+4=8y-4+6y

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    posted by erick

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