Find the area and perimeter of a room with dimensions of 8,5 metres by 9,3 metres
A = LW
P = 2L + 2W
I'll be glad to check your answers.
Area = 8.5 * 9.3
Perimeter = 2(8.5) + 2(9.3)
To find the area of a rectangular room, you multiply the length (L) by the width (W). In this case, the length is 8.5 meters and the width is 9.3 meters.
Area = Length × Width
Area = 8.5 m × 9.3 m
Area = 79.05 square meters
So, the area of the room is 79.05 square meters.
Now, let's calculate the perimeter of the room. The perimeter is the sum of all the sides of the rectangle. In this case, there are two equal lengths of 8.5 meters and two equal widths of 9.3 meters.
Perimeter = 2 × (Length + Width)
Perimeter = 2 × (8.5 m + 9.3 m)
Perimeter = 2 × 17.8 m
Perimeter = 35.6 meters
Therefore, the perimeter of the room is 35.6 meters.