The length of a rectangle is three more than twice its width. Its perimeter is 24 inches. Find its dimensions length and width.
perimeter 24 = 2*length + 2*width
so, ...
The length of a rectangle is to more than three times it's with his perimeter is 36 find its dimensions
To find the dimensions of the rectangle, we can start by assigning variables to represent the length and width. Let's say the width of the rectangle is "w" inches.
According to the problem, "the length of a rectangle is three more than twice its width." This can be expressed as:
Length = 2w + 3
The formula for the perimeter of a rectangle is given by:
Perimeter = 2(length + width)
Since we know the perimeter is 24 inches, we can substitute the given values into the formula:
24 = 2((2w + 3) + w)
Now, let's solve for the width:
24 = 2(3w + 3)
Divide both sides by 2:
12 = 3w + 3
Subtract 3 from both sides:
9 = 3w
Divide both sides by 3:
w = 3
Now that we know the width is 3 inches, we can substitute this value back into the equation for the length:
Length = 2w + 3
Length = 2(3) + 3
Length = 6 + 3
Length = 9
Therefore, the dimensions of the rectangle are:
Length = 9 inches
Width = 3 inches