In triangle ABC,if m∠A is thirteen less than m∠C and m∠B is eleven less than four times m∠C, find the measurement of each angle.
A+B+C= 180
A= 13-C
B= 4C-11
This did not help. I tried this and the ending up result did not end up to be 180
Shouldn't it be C-13 instead?
it says 13 LESS THAN not C is less than
In ABC, if mA is thirteen less than mC and mB is eleven less than four times mC, find the measure of each angle.
To solve this problem, we'll use the information provided and set up an equation.
Let's substitute the values we have into the equation A + B + C = 180:
(13 - C) + (4C - 11) + C = 180
Now we can simplify the equation:
13 - C + 4C - 11 + C = 180
13 + 3C - 11 = 180
3C + 2 = 180
3C = 178
C = 178/3
Now that we have the value of C, we can find the values of A and B using the given equations:
A = 13 - C
B = 4C - 11
Substituting the value of C:
A = 13 - (178/3)
B = 4(178/3) - 11
Now we can calculate the values of A and B:
A = 13 - (178/3) ≈ -48.33
B = (4(178/3)) - 11 ≈ 92.67
Therefore, the measurements of each angle in the triangle ABC are approximately:
Angle A ≈ -48.33 degrees
Angle B ≈ 92.67 degrees
Angle C ≈ 178/3 degrees (approximately 59.33 degrees)
good work so far. Now just solve the equations.
Plug in the expressions for A and B, and you can then solve for C.
Then work back to evaluate A and B, using the value of C.