Mr.Jacobs budgeted $1,200 for tiles.His sketch of the floor requires him to use 38 white tiles.Each white tile costs $12.Write and solve an inequality to find the maximum amount he can spend on brown tiles.

x + 38*12 <= 1200

2856/500

(38*12)+b <= 1200

To find the maximum amount Mr. Jacobs can spend on brown tiles, we need to set up an inequality based on his budget and the cost of the white tiles.

Let's use the variable x to represent the number of brown tiles. The cost of each brown tile is not given, so let's assume it costs $b.

The cost of the white tiles is given as $12 each, and Mr. Jacobs needs 38 white tiles. So the cost of the white tiles would be 12 * 38 = $<<12*38=456>>456.

The cost of the brown tiles would be x * b.

To find the maximum amount he can spend on brown tiles, we need to ensure that the total cost (cost of white tiles + cost of brown tiles) does not exceed his budget of $1,200.

Therefore, the inequality can be written as:

456 + x * b ≤ 1200

This inequality ensures that the cost of the white tiles and brown tiles combined does not exceed the budget.

Now, since we are trying to find the maximum amount he can spend on brown tiles, we need to solve this inequality for x.

To do so, we would need more information about the cost of the brown tiles (value of b) or more constraints to narrow down the possible values for x. Without that information, it is not possible to solve the inequality and find the maximum amount he can spend on brown tiles.