James and his friends rolled two fair number cubes 500 times and recorded the sum of the numbers shown on the cubes each time.On 42 of the trials the sum was 10.Which of these is most likely the probability that the sum of the numbers shown on the cubes is 10 when two fair number cubes are rolled?
which of what ways> I don't see choices.
if the dice are fair, one would expect a frequency of 1/12 (2*1/36+1/36)
so in 500 trials, the best guess is 500/12=40.7 times. SO one should bet on 41, 42, 40, or 39 as being the most frequent, with 41 being the highest frequency.
To find the most likely probability that the sum of the numbers shown on the cubes is 10 when two fair number cubes are rolled, we need to calculate the ratio of the number of successful outcomes (sum is 10) to the total number of possible outcomes.
In this case, James and his friends rolled the number cubes 500 times and recorded the sum each time. Out of those 500 trials, the sum was 10 on 42 occasions.
Therefore, we can calculate the probability as follows:
Probability = Number of successful outcomes / Total number of possible outcomes
Probability = 42 / 500
Simplifying this fraction, we get:
Probability = 21 / 250
Hence, the most likely probability that the sum of the numbers shown on the cubes is 10 when two fair number cubes are rolled is 21/250.