The Jacobys went on a 600-mile trip. On the first day they drove 5 3/4 hours and on the second day they drove 4 3/4 hours. How many hours did they drive during the first two days?
5 3/4 + 4 3/4 = 9 6/4 = 10 2/4 = 10 1/2 hours
what's the answer!!!!!!!!
To find the total number of hours the Jacobys drove during the first two days, you need to add the number of hours they drove on the first day and the number of hours they drove on the second day.
On the first day, they drove for 5 3/4 hours. To add this to the total, you can convert the mixed number 5 3/4 into an improper fraction. To do this, multiply the whole number (5) by the denominator of the fraction (4) and then add the numerator (3). The result is 5 * 4 + 3 = 20 + 3 = 23. So, 5 3/4 is equal to 23/4.
On the second day, they drove for 4 3/4 hours. Similar to the previous step, convert 4 3/4 into an improper fraction. Multiply the whole number (4) by the denominator (4), and add the numerator (3). You get 4 * 4 + 3 = 16 + 3 = 19. So, 4 3/4 is equal to 19/4.
Now add the fractions: 23/4 + 19/4. To add them, you need to find a common denominator, which is already 4 in this case. Simply add the numerators together: 23 + 19 = 42. So, the total number of hours they drove during the first two days is 42/4.
However, to express this as a mixed number (a whole number and a fraction), divide the numerator (42) by the denominator (4). The result is a whole number of 10, with a remainder of 2. So, 42/4 is equal to 10 2/4.
Since 2/4 can be simplified to 1/2, the final answer is 10 1/2 hours. Therefore, during the first two days, the Jacobys drove for a total of 10 1/2 hours.