The sum of two consecutive counting

numbers divided by their positive difference is 9.
Find the larger numbers.

well their difference is one :)

4 + 5 = 9

To solve this problem, let's first understand what the problem is asking.

We are looking for two consecutive counting numbers. Let's assume the first number is represented by "x" and the second number is represented by "x + 1". The positive difference between these two numbers is 1.

According to the problem, the sum of these two consecutive counting numbers divided by their positive difference is 9.

Mathematically, we can represent this situation using the following equation:

(x + (x + 1)) / 1 = 9

Now, let's solve this equation to find the larger number (x + 1).

Simplifying the equation, we get:

(2x + 1) / 1 = 9

To isolate the variable, we can multiply both sides of the equation by 1:

2x + 1 = 9

Next, let's isolate the variable x by subtracting 1 from both sides:

2x = 9 - 1
2x = 8

Finally, divide both sides of the equation by 2 to solve for x:

x = 8 / 2
x = 4

So, the first number is 4. To find the larger number (x + 1), we add 1 to x:

x + 1 = 4 + 1
x + 1 = 5

Therefore, the larger number is 5.

let the consecutive numbers be 4 and 5.4+5÷4+5=9÷9=1